x^2+100x-3360=0

Solution for x^2+100x-3360=0 equation:

x^2+100x-3360=0

a = 1; b = 100; c = -3360;
Δ = b2-4ac
Δ = 1002-4·1·(-3360)
Δ = 23440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{23440}=\sqrt{16*1465}=\sqrt{16}*\sqrt{1465}=4\sqrt{1465}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{1465}}{2*1}=\frac{-100-4\sqrt{1465}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{1465}}{2*1}=\frac{-100+4\sqrt{1465}}{2}
$